HW4s - Prob. 1 WOR qw/qo Sw increasing Swr Sor Sw 0.51...

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Prob. 1 WOR qw/qo fw/(1-fw) 1 fw= WOR/1+WOR 0.5 Sw increasing Imbibitionkro 0.75(1-SwD)2 krw 0.1 (SwD)2 Swr 0.3 vw 0.5 Sor 0.25 vo 5 fw (krw/vw)/[(kro/vo)+(krw/vw)] Sw SwD krw kro fw fw-0.5 0.51 0.46 0.02 0.22 0.5 0 Prob. 2 K (md) 60 L (cm) 7.5 A (cm2) 7.89 Porosity 0.23 PV (cm3) 13.85 kw vw.qw.L/dp.A Swr 0.3 Ko0 (md) 43.7 vw, cp 0.77 dw, g/ml 0.99 Sor 0.27 Kw0 (md) 18.5 vo, cp 1.2 do, g/ml 0.75 Wd, g 178.88 Ww, g 192.66 W(Sw) Wd+(Sw.PV.dw)+[(1-Sw).PV.do] Run t,s Qw, ml Qo, ml dp, atm W Sw W-W calc qw, ml/s qo, ml/s kw, md ko, md krw 1 311.6 0.7 9.32 0.98 190.54 0.38 0 0 0.03 1.66 34.71 0.03 2 331.1 1.93 8.04 1.02 190.84 0.46 0 0.01 0.02 4.16 27.16 0.07 3 349.3 3.5 6.53 1.17 191.04 0.52 0 0.01 0.02 6.24 18.23 0.1 4 343.2 5.78 4.22 1.24 191.26 0.59 0 0.02 0.01 9.89 11.31 0.16 5 336.5 7.9 2.1 1.34 191.43 0.64 0 0.02 0.01 12.76 5.31 0.21 0.3 0 43.7 0 0.73 18.5 0 0.31
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kro 0.58 0.45 0.3 0.19 0.09 0.73 0
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Prob. 3 A waterflood is considered for a narrow, shoestring reservoir. It is proposed to drill a row of injection wells at one end and flood the reservoir by injecting water
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This note was uploaded on 10/11/2009 for the course PGE 19460 taught by Professor Sharma during the Spring '09 term at University of Texas at Austin.

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HW4s - Prob. 1 WOR qw/qo Sw increasing Swr Sor Sw 0.51...

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