{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Practice Homework 7

# Practice Homework 7 - practice 07 ALIBHAI ZAHID Latest...

This preview shows pages 1–4. Sign up to view the full content.

practice 07 – ALIBHAI, ZAHID 1 Latest unpenalized work: Mar 4 2007 Sunday 04:00 (after this date you can not make a perfect score). Work cutoff: Mar 4 2007, 4:00 am. Question 1 part 1 of 1 10 points Two identical stars, a fixed distance D apart, revolve in a circle about their mutual center of mass, as shown below. Each star has mass M and speed v . G is the universal gravitational constant. D v v M M Which of the following is a correct relation- ship among these quantities? 1. v 2 = G M D 2 2. v 2 = 2 G M D 3. v 2 = 4 G M 2 D 4. v 2 = M G D 5. v 2 = 2 G M 2 D 6. v 2 = G M 2 D 7. v 2 = 4 G M D 8. v 2 = G M D Question 2 part 1 of 2 10 points Compare the gravitational force on a 45 . 5 kg mass at the surface of the Earth ( R E = 6 . 4 × 10 6 m, M E = 6 × 10 24 kg) with that on the surface of the Moon ( M M = 1 81 . 3 M E , R M = 0 . 27 R E ). What is it on the Earth? Answer in units of N. Question 3 part 2 of 2 10 points What is it on the Moon? Answer in units of N. Question 4 part 1 of 1 10 points If a book is sitting on a table, the force of gravity is pulling it down. Why doesn’t it fall? 1. The book has a pushing force on the table. 2. The book is not heavy enough. 3. The table is pushing up on it with a force equal to the weight of the book. Question 5 part 1 of 2 10 points Given: G = 6 . 6726 × 10 11 N m 2 / kg 2 . Three masses are arranged in the ( x, y ) plane (as shown in the figure below, where the scale is in meters). y ( m ) 5 3 1 0 1 2 3 4 5 x ( m ) 5 4 3 2 1 0 1 2 3 4 5 6 kg 3 kg 4 kg What is the magnitude of the resulting force

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
practice 07 – ALIBHAI, ZAHID 2 on the 6 kg mass at the origin? Answer in units of N. Question 6 part 2 of 2 10 points Select the figure showing the direction re- sultant force on the 6 kg masses at the origin. 1. y 5 3 10 1 2 3 4 5 x 5 4 3 2 1 0 1 2 3 4 5 2. y 5 3 10 1 2 3 4 5 x 5 4 3 2 1 0 1 2 3 4 5 3. y 5 3 10 1 2 3 4 5 x 5 4 3 2 1 0 1 2 3 4 5 4. y 5 3 10 1 2 3 4 5 x 5 4 3 2 1 0 1 2 3 4 5 5. None of these figures is correct. 6. y 5 3 10 1 2 3 4 5 x 5 4 3 2 1 0 1 2 3 4 5 7. y 5 3 10 1 2 3 4 5 x 5 4 3 2 1 0 1 2 3 4 5 Question 7 part 1 of 2 10 points The universal gravitationan constant is 6 . 6726 × 10 11 N m 2 / kg 2 . Three 5 kg masses are located at points in the xy plane as shown in the figure. 32 cm 51 cm What is the magnitude of the resultant force (caused by the other two masses) on the mass at the origin? Answer in units of N. Question 8 part 2 of 2 10 points At what angle from the horizontal ( x ) axis will the resultant force point? Answer in units of .
practice 07 – ALIBHAI, ZAHID 3 Question 9 part 1 of 1 10 points Consider an airless, non-rotating planet of mass M and radius R . An electromagnetic launcher standing on the surface of this planet shoots a projectile with initial velocity v 0 di- rected straight up. Unfortunately, due to some error, v 0 is less than the planet’s escape velocity v e . Specifically, v 0 = 0 . 843 v e .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern