{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Practice Homework 11

Practice Homework 11 - practice 11 ALIBHAI ZAHID Latest...

This preview shows pages 1–3. Sign up to view the full content.

practice 11 – ALIBHAI, ZAHID 1 Latest unpenalized work: Apr 8 2007 Sunday 04:00 (after this date you can not make a perfect score). Work cutoff: Apr 8 2007, 4:00 am. Question 1 part 1 of 1 10 points Two weights attached to a uniform beam of mass 38 kg are supported in a horizontal position by a pin and cable as shown in the figure. The acceleration of gravity is 9 . 8 m / s 2 . 23 kg 20 kg 2 . 9 m 8 m 37 38 kg What is the tension in the cable which sup- ports the beam? Answer in units of kN. Question 2 part 1 of 3 10 points A uniform rod pivoted at one end “point O ” is free to swing in a vertical plane in a gravitational field. However, it is held in equilibrium by a force F at its other end. x y F F x F y W R x R R y θ O Force vectors are drawn to scale. What is the condition for translational equilibrium along the horizontal x direction? 1. F x = 0 2. - R x + F x = 0 3. R x - F x cos θ = 0 4. R x - F x sin θ = 0 5. F x cos θ - R x sin θ = 0 Question 3 part 2 of 3 10 points What is the condition for translational equilibrium along the vertical y direction? 1. R y + F y - W = 0 2. R y - F y + W = 0 3. R y + F y = 0 4. R y sin θ + F y sin θ - W cos θ = 0 5. W - R y + F y = 0 Question 4 part 3 of 3 10 points Taking the origin (point O ) as the pivot point, what is the condition for rotational equilibrium? 1. F y sin θ - W 2 sin θ - F x sin θ = 0 2. F y cos θ - W 2 cos θ - F x sin θ = 0 3. 2 F y sin θ - W ℓ cos θ - 2 F x sin θ = 0 4. W 2 - F x cos θ - F y cos θ = 0 5. F y cos θ - W ℓ sin θ + F x sin θ = 0 Question 5 part 1 of 1 10 points A light string has its ends tied to two walls

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
practice 11 – ALIBHAI, ZAHID 2 separated by a distance equal to four-fifth the length L of the string as shown in the figure. A 25 kg mass is suspended from the center of the string, applying a tension in the string. The acceleration of gravity is 9 . 8 m / s 2 . 4 L 5 25 kg L 2 L 2 θ θ What is the tension in the two strings of length L 2 tied to the wall? Answer in units of N. Question 6 part 1 of 1 10 points A solid bar of length L has a mass m 1 . The bar is fastened by a pivot at one end to a wall which is at an angle θ with respect to the horizontal. The bar is held horizontally by a vertical cord that is fastened to the bar at a distance x cord from the wall. A mass m 2 is suspended from the free end of the bar. T m 2 m 1 θ x cord L Find the tension T in the cord. 1. T = parenleftbigg m 1 + 1 2 m 2 parenrightbigg parenleftbigg L x cord parenrightbigg g cos θ 2. T = parenleftbigg m 1 + 1 2 m 2 parenrightbigg parenleftbigg L x cord parenrightbigg g 3. T = ( m 1 + m 2 ) parenleftbigg L x cord parenrightbigg parenleftBig g 2 parenrightBig 4. T = parenleftbigg 1 2 m 1 + m 2 parenrightbigg parenleftbigg L x cord parenrightbigg g cos θ 5. T = ( m 1 + m 2 ) g cos θ 6. T = parenleftbigg m 1 + 1 2 m 2 parenrightbigg parenleftbigg L x cord parenrightbigg g sin θ 7. T = parenleftbigg 1 2 m 1 + m 2 parenrightbigg parenleftbigg L x cord parenrightbigg g sin θ 8. T = 0 9. T = parenleftbigg 1 2 m 1 + m 2 parenrightbigg parenleftbigg L x cord parenrightbigg g 10. T = ( m 1 + m 2 ) g sin θ Question 7
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 9

Practice Homework 11 - practice 11 ALIBHAI ZAHID Latest...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online