Practice Homework 8

Practice Homework 8 - practice 08 – ALIBHAI ZAHID 1...

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Unformatted text preview: practice 08 – ALIBHAI, ZAHID 1 Latest unpenalized work: Mar 19 2007 Mon- day 04:00 (after this date you can not make a perfect score). Work cutoff: Mar 19 2007, 4:00 am. Question 1 part 1 of 3 10 points Two small spheres of mass m 1 and m 2 are suspended from the ceiling at the same point by massless strings of equal length ℓ . The lighter sphere is pulled aside through an angle of θ i from the vertical and let go. The acceleration of gravity is 9 . 8 m / s 2 . g Before m 1 ℓ θ i m 2 g After θ f At what speed will the lighter mass m 1 hit the heavier mass m 2 ? 1. v 1 i = { g ℓ [cos θ i ] } 2. v 1 i = { 2 g ℓ [cos θ i ] } 1 2 3. v 1 i = { 2 g ℓ [1- cos θ i ] } 4. v 1 i = { 2 g ℓ [1- cos θ i ] } 1 2 5. v 1 i = { g ℓ [1- cos θ i ] } 6. v 1 i = { g ℓ [1- cos θ i ] } 1 2 7. v 1 i = { 2 g ℓ [cos θ i ] } 8. v 1 i = { g ℓ [cos θ i ] } 1 2 Question 2 part 2 of 3 10 points After lighter sphere is let go and collides with the heavier sphere at the bottom of its swing, two spheres immediately bind to- gether. What is conserved in this collision process? Let E = mechanical energy; P = momentum. 1. E 2. Both E and P 3. P 4. Neither E nor P Question 3 part 3 of 3 10 points After the lighter sphere is let go and col- lides with the heavier sphere at the bottom of its swing, the two spheres immediately bind together. What is the speed V f of the combined sys- tem just after the collision? 1. V f = parenleftbigg m 1 + m 2 2 m 2 parenrightbigg v 1 i 2. V f = parenleftbigg m 1 + m 2 2 m 1 parenrightbigg v 1 i 3. V f = parenleftbigg m 2 m 1 + m 2 parenrightbigg v 1 i 4. V f = parenleftbigg m 1 + m 2 m 2 parenrightbigg v 1 i 5. V f = parenleftbigg 2 m 2 m 1 + m 2 parenrightbigg v 1 i 6. V f = parenleftbigg 2 m 1 m 1 + m 2 parenrightbigg v 1 i 7. V f = parenleftbigg m 1 m 1 + m 2 parenrightbigg v 1 i practice 08 – ALIBHAI, ZAHID 2 8. V f = parenleftbigg m 1 + m 2 m 1 parenrightbigg v 1 i Question 4 part 1 of 2 10 points A block of mass 66 kg slides along a fric- tionless table with a speed of 70 m / s. Directly in front of it, and moving in the same direc- tion with a speed of 22 m / s, is a block of mass 32 kg. A massless spring with spring constant 1305 N / m is attached to the second block as in the figure. 66 kg 70 m / s 1305 N / m 32 kg 22 m / s During the collision, the spring is com- pressed by a maximum amount Δ x . What is this maximum compression? Hint: work in an inertial frame in which p 1 + p 2 = 0 . Answer in units of m. Question 5 part 2 of 2 10 points The blocks will eventually separate again. What is the final velocity of the 66 kg block? Answer in units of m / s. Question 6 part 1 of 1 10 points A disc of mass m moves horizontally to the right with speed v on a table with negligible friction when it collides with a second disc of mass 5 m . The second disc is moving horizon- tally to the right with speed v 9 at the moment of impact....
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Practice Homework 8 - practice 08 – ALIBHAI ZAHID 1...

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