Homework 14 - homework 14 BAUTISTA, ALDO Due: Feb 24 2006,...

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homework 14 – BAUTISTA, ALDO – Due: Feb 24 2006, 4:00 am 1 Version number encoded for clicker entry: V1:1, V2:4, V3:2, V4:4, V5:3. Question 1 Part 1 of 1. 10 points. Use the potential energy vs . position plot shown below to answer the following question. A particle is released from point A and moves in the potential U ( x ). Suppose the mechanical energy of the system is conserved. x U ( x ) Y T V A At which position(s) will the kinetic energy of the particle have its maximum value? 1. Point V . correct 2. Point T . 3. Point Y . 4. The particle remains stationary at point A . 5. Points Y and V . Explanation: Since the total energy is constant, the max- imum kinetic energy will occur when the po- tential energy is a minimum. Thus point V is the correct answer. Question 2 Part 1 of 2. 10 points. While skiing in Jackson, Wyoming, your friend Ben (82 kg) started his descent down the bunny run, 29 m above the bottom of the run. If he started at rest and converted all of his gravitational potential energy into kinetic energy, what is Ben’s kinetic energy at the bottom of the bunny run? Correct answer: 23304 . 4 J (tolerance ± 1 %). Explanation: Let : m = 82 kg , g = 9 . 8 m / s 2 , and h = 29 m . KE = P E = m g h = (82 kg) (9 . 8 m / s 2 ) (29 m) = 23304 . 4 J . Question 3 Part 2 of 2. 10 points. What is his ±nal velocity? Correct answer: 23 . 8411 m / s (tolerance ± 1 %). Explanation:
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This note was uploaded on 10/13/2009 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas at Austin.

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Homework 14 - homework 14 BAUTISTA, ALDO Due: Feb 24 2006,...

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