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Practice Homework 13 Solutions

# Practice Homework 13 Solutions - practice 13 ALIBHAI ZAHID...

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practice 13 – ALIBHAI, ZAHID – Due: Apr 22 2007, 4:00 am 2 y L d S 1 S 2 θ listening direction θ δ Find the separation between the two sources. Correct answer: 1 . 548 m (tolerance ± 1 %). Explanation: Let : f = 540 Hz , v = 340 m / s , θ 1 = 0 , and θ 2 = 24 . r 2 r 1 y L d S 1 S 2 θ = tan 1 parenleftBig y L parenrightBig listening direction δ d sin θ r 2 r 1 P O negationslash S 2 Q S 1 90 Q 2 π or 360 φ δ λ = 500 0 1 1 0 90 180 270 360 0 π/ 2 π 3 π/ 2 2 π φ 2 π = δ λ = d sin θ λ = d λ y radicalbig L 2 + y 2 d λ y L Because a maximum is heard at 0 and the sources are in phase, we can conclude that the path difference is 0. Because the next maximum is heard at 24 , the path difference to that position must be one wavelength: sin θ = Δ s d d = λ sin θ = v f sin θ = 340 m / s (540 Hz) sin 24 = 1 . 548 m . Question 5 part 2 of 2 10 points Find the next larger angle at which a max- imum intensity will be heard. Correct answer: 54 . 4367 (tolerance ± 1 %). Explanation: For additional intensity maxima, d sin θ m = mλ, m = 2 , 3 , 4 , ...
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Practice Homework 13 Solutions - practice 13 ALIBHAI ZAHID...

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