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Unformatted text preview: gd Q L h f = and 4 2 2 2 128 gd Q L h f = . We can substitute head losses in the energy conservation equation above. Noting that z 1 =z 2 we can simplify to get: Pa d L d L d V V V p p p 525 , 104 128 2 2 4 2 2 4 1 1 1 1 2 1 2 2 2 1 + + = = . Required force F is: N d p A p F 25 . 2 4 2 1 = = =...
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This note was uploaded on 10/12/2009 for the course MAE 210318200 taught by Professor Kulinsky during the Spring '09 term at UCLA.
 Spring '09
 Kulinsky

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