p0160

# p0160 - P This force must still balance the weight of the...

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1.60. CHAPTER 1, PROBLEM 60 61 1.60 Chapter 1, Problem 60 Figure 1.6: Rectangular cross-section capillary tube of sides s × 4 s . The difference between this problem and the example worked in the text is the shape of the cross-sectional area of the capillary tube. Regardless of the shape of the cross section, the force due to surface tension is the product of σ and the distance around the perimeter of the cross section,
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Unformatted text preview: P . This force must still balance the weight of the column of fluid, so that P σ cos φ = ρ g ∆ hA = ⇒ ∆ h = P σ ρ gA cos φ where φ is the wetting angle and A is the cross-sectional area of the capillary tube. Now, for a rectangular tube s wide and 4 s thick, A = 4 s 2 and P = 10 s . Hence, ∆ h = 10 s σ ρ g (4 s 2 ) cos φ = 5 2 σ ρ gs cos φ...
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