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Unformatted text preview: there must be 1 additional dimensionless grouping. In the present case, this means there is one such grouping. We can solve the first and third equations immediately for a 1 and a 2 , i.e., a 1 = 1 2 and a 2 = − 1 2 Substituting the values of a 1 and a 2 into the dimensional equation, we have [ u τ ] = [ τ w ] 1 / 2 [ ρ ] − 1 / 2 Therefore, we expect u τ to vary according to u τ = constant · ± τ w ρ Selecting a value of one for the constant, we conclude that u τ = ± τ w ρ...
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This note was uploaded on 10/12/2009 for the course AME 309 at USC.