p0282 - g m L m g p L p = L p L m = L m = L p X g p g m ~ 1...

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2.82. CHAPTER 2, PROBLEM 82 219 2.82 Chapter 2, Problem 82 To achieve dynamic similitude, we must match Reynolds and Froude numbers. Hence, since the model and prototype fluids are identical, ν m = ν p , wherefore U m L m ν m = U p L p ν p = U m U p = L p L m U m g m L m = U p ± g p L p = U m U p = ² g m L m g p L p So, equating these two expressions for the velocity ratio, we have
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Unformatted text preview: g m L m g p L p = L p L m = L m = L p X g p g m ~ 1 / 3 Also, U m = U p X g m g p ~ 1 / 3 We are given L p = 2 m, U p = 5 m/sec and g m = 6 g p . Thus, L m = (2 m) w 1 6 W 1 / 3 = 1 . 10 m U m = w 5 m sec W 6 1 / 3 = 9 . 09 m sec...
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This note was uploaded on 10/12/2009 for the course AME 309 at USC.

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