p0328 - , 1 Points C D and p D = p a + g 6 h = p a + 6 gh ,...

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278 CHAPTER 3. EFFECTS OF GRAVITY ON PRESSURE 3.28 Chapter 3, Problem 28 First, label boundaries between fluids as indicated in Figure 3.13. Figure 3.13: Three-fluid manometer. Using the hydrostatic relation, we have the following two equations: p A = p B + 1 2 ρ g · 3 h = p B + 3 2 ρ gh ± 1 Points B A and p C = p B ρ g · 2 h = p B +2˜ ρ gh ± 1 Points B C Hence ,thepressurea tPo in tsBandAare : p B = p C ρ gh and p A = p C + 3 2 ρ gh ρ gh Also, applying the hydrostatic relation at elevation D from both sides of the tank to the left, we find: p D = p C + ρ g · 3 h =
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Unformatted text preview: , 1 Points C D and p D = p a + g 6 h = p a + 6 gh , 1 Points O D Eliminating p D , we thus find p C + 3 gh = p a + 6 gH = p C = p a + 3 gh So, the pressure at Point A is p A = ( p a + 3 gh ) + 3 2 gh 2 gh = p a + 9 2 gh 2 gh Finally, we are given p A = p a + 4 . 2 gh so that 4 . 2 gh = 9 2 gh 2 gh Therefore, the density is = 0 . 15...
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