p0378 - 3 . Thus, V = 51 N 33 N p 998 kg / m 3 Q p 9 . 807...

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336 CHAPTER 3. EFFECTS OF GRAVITY ON PRESSURE 3.78 Chapter 3, Problem 78 If the object’s weight is W andthefo rcetol if ti twhensubme rgedis F , then W = F + F buoy = F + ρ gV So, the volume of the cement slab is V = W F ρ g We are given W
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Unformatted text preview: 3 . Thus, V = 51 N 33 N p 998 kg / m 3 Q p 9 . 807 m / sec 2 Q = 1 . 839 10 3 m 3 = 1839 cm 3 Also, W = gV = = W gV = 51 N p 9 . 807 m / sec 2 Q (1 . 839 10 3 m 3 ) = 2828 kg m 3...
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