{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

p0378 - 3 Thus V = 51 N βˆ’ 33 N p 998 kg m 3 Q p 9 807 m...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
336 CHAPTER 3. EFFECTS OF GRAVITY ON PRESSURE 3.78 Chapter 3, Problem 78 If the object’s weight is W and the force to lift it when submerged is F , then W = F + F buoy = F + ρ gV So, the volume of the cement slab is V = W F ρ g We are given W = 51 N and F = 33 N. Also for 20 o C, the density of water is 998 kg/m
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 3 . Thus, V = 51 N βˆ’ 33 N p 998 kg / m 3 Q p 9 . 807 m / sec 2 Q = 1 . 839 Β· 10 βˆ’ 3 m 3 = 1839 cm 3 Also, W = ρ gV = β‡’ ρ = W gV = 51 N p 9 . 807 m / sec 2 Q (1 . 839 Β· 10 βˆ’ 3 m 3 ) = 2828 kg m 3...
View Full Document

{[ snackBarMessage ]}