p0542 - Then, from Bernoullis equation, p B + 1 2 ( U I B )...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
500 CHAPTER 5. CONSERVATION OF MASS AND MOMENTUM 5.42 Chapter 5, Problem 42 We must make a Galilean transformation in order to make the flow steady, wherefore we can use Bernoulli’s equation. The velocities transform as indicated in Figure 5.20. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .................... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ..................... . . . . . . . . . . . . ..................................... . . . . . . ............. . . . . . . . ....... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .... . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . ... .... (Unsteady) U A =15 q U B =4 q U C =2 q U =0 q (Steady) U I A =0 q U I B =11 q U I C =13 q U I =15 q Figure 5.20: Galilean transformation details.
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Then, from Bernoullis equation, p B + 1 2 ( U I B ) 2 = p C + 1 2 ( U I C ) 2 = p B p C = 1 2 ( U I C ) 2 ( U I B ) 2 = Hence, since the density of water is 1000 kg/m 3 , the pressure difference is p B p C = 1 2 X 1000 kg m 3 ~ X 169 m 2 sec 2 121 m 2 sec 2 ~ = 24 10 3 kg m sec 2 = 24 kPa...
View Full Document

Ask a homework question - tutors are online