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Unformatted text preview: 8 s 8 S ( u u cv ) n dS = w 5 3 W k W k 4 p D 2 d 2 Q = 5 12 W p D 2 d 2 Q Thus, the massconservation equation simplifies to 4 WD 2 + 5 12 W p D 2 d 2 Q = D 2 = 5 2 d 2 566 CHAPTER 6. CONTROLVOLUME METHOD Therefore, the plunger velocity matches the velocity of the fluid forced out of the cone when D = 5 2 d Finally, the cone shape is such that D = 0 at z = 0 and D = 2 d at z = 80 d . Thus, in general D = 1 40 z Hence, we have 1 40 z = 5 2 d = z = 40 5 2 d = 63 . 2 d...
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This note was uploaded on 10/12/2009 for the course AME 309 at USC.
 '06
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