ProblemSet 1: Problem 2.Problem:FindM×NifM=2i−2j−kandN=i+j+k.Solution:For the given vectors, we haveM×N=eeeeeeeijk2−2−1111eeeeeee=(−2+1)i−(2 + 1)j+(2+2)kwhere the second equality follows from expanding in cofactors. Doing the arithmetic, we find
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This note was uploaded on 10/12/2009 for the course AME 301 at USC.