classes_Spring08_172ID39_ProblemSet4_solutions

classes_Spring08_172ID39_ProblemSet4_solutions - Chemistry...

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1 Chemistry 172/273 Problem Set #4 Due on Friday, June 6, in class Spring 2008 Note : Do not use a pencil. Use black ink only. Try to write as neatly as possible. If I don’t understand your handwriting, you will not get any points. 1 . The high-spin d 4 complex [Cr(OH 2 ) 6 ] 2+ is labile, but the low-spin d 4 complex [Cr(CN) 6 ] 4- is inert. Explain. [Cr(OH 2 )] 2+ d 4 high-spin, while [Cr(CN) 6 ] 4- is d 4 low spin. The Cr-CN bond is much stronger than the Cr-OH 2 bond (due to the π back-bonding). 2 . Predict whether these complexes would be labile or inert and explain your choices. For each complex the magnetic moment is given in Bohr magnetons: Ammonium oxopentachlorochromate(V) 1.82 Potassium hexaiodomanganate(IV) 3.82 Potassium hexacyanoferrate(III) 2.40 Hexaammineiron(II) chloride 5.45 [NH 4 ][CrOCl 5 ]: Cr(V), d 1 ; labile K 2 MnI 6 : Mn(IV), d 3 ; inert, same as Cr(III) K 3 Fe(CN) 6 : Fe(III), d 5 , low spin; inert [Fe(NH 3 ) 6 ]Cl 2 : Fe(II), d 6 , high spin; labile 3 . Account for the observation that two separate water exchange rates are found for [Cu(OH 2 ) 6 ] 2+ in solution.
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classes_Spring08_172ID39_ProblemSet4_solutions - Chemistry...

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