!"#$%&’ )*+
Find I
o
in the circuit shown using linearity and the assumption that I
o
= 1mA.
4mA
4K
Ω
4K
Ω
4K
Ω
2K
Ω
4K
Ω
12K
Ω
I
2
I
3
+
+
-
V
1
1
o
k
I
A
=
I
1
-
,-..&/0&1 ,#%-02#3
I
T
4K
Ω
4K
Ω
4K
Ω
2K
Ω
4K
Ω
12K
Ω
I
2
I
3
+
+
-
V
1
1
o
k
I
A
=
I
1
-
V
2
4/K A
6
3
1
1
o
2
1
k
k
4k
2
5
2
1
2
1
2
2
V2
7
3
2
3
4K + 12K
2
7/2mA
8
4mA
1mA
x
7
I =
(4
2
)
6
,
4
16
1
o
T
o
A
V
K
K
V
I
mA
I
I
I
mA
V
V
KI
V
I
mA
I
I
I
mA
x
I
mA
=
+
=
=
=
=
+
=
=
+
=
=
=
∴
=
+
=
=
∴
=
=
If
Then
Then
and
Then
So
!"#$%&’ )*
8
Find Vo in the network shown using superposition
3K
Ω
3K
Ω
Vo
+
-
3K
Ω
3K
Ω
9V
6K
Ω
,-..&/0&1 ,#%-02#3
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