CAE303F07HW_2Solution

# CAE303F07HW_2Solution - CAE 303 FALL 2007 STRUCTURAL DESIGN...

This preview shows pages 1–3. Sign up to view the full content.

CAE303 Solution Set # 2 CAE 303 – FALL 2007 STRUCTURAL DESIGN I: STEEL STRUCTURES Instructor: J. Shen, Ph.D.,P.E., S.E. Problem 1 (a) Solution: T d r t PL 8 × 5/8 Bolts: d=3/4 inch for Standard punched holes Bolts d net =d h +1/16=13/16+1/16=7/8 in. 51 3 5 8 3 3.48 81 6 8 g nn e t AA d t =− = × × × = in 2 Answer (b) Solution : P S PL 8 × 5/8 Bolts: d=3/4 inch for Standard punched holes Bolts d net =d h +1/16=3/8+1/16=13/16 in. Path a – b – c – d 3 5 8 2 3.98 6 8 ng n e t d t = × × × = in 2 Path a – b – e – c – d, s=1.5 in 2 g=2.75 in 2 22 3 5 1 . 5 5 83 2 3 . 7 3 4 8 16 8 4 2.75 8 n e t s d t g + = × × × + × × = × ∑∑ in 2 <3.98 in 2 A n =3.73 in 2 Answer g e c a b d 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Problem 2 (a) Shaded portion equivalent to WT7 × 41 3 3 Solution : WT 7 41, × 1.39 pt xy == in., 22 3 . 0 6 . Lp 0 = =× = in. 1/ 1 1 . 3 9 / 6 . 0 0 . 7 7 Ux p =− = , WT 14 82, d=14.3,b f =10.1, b f × 2 3 d =9.53 Table D3.1 of SPEC U=0.90 U=max (0.77,0.90)=0.90 Answer (b) WT7 × 45 T Solution : WT 7 45, × 1.09 pt in., 3 . 0 6 . 0 = in.
This is the end of the preview. Sign up to access the rest of the document.

## This homework help was uploaded on 04/07/2008 for the course CAE 303 taught by Professor Shen during the Fall '08 term at Illinois Tech.

### Page1 / 4

CAE303F07HW_2Solution - CAE 303 FALL 2007 STRUCTURAL DESIGN...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online