mont4e_sm_ch09_sec04 - Section 9-4 9-63 a) =0.01, n=20,...

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9-29 Section 9-4 9-63 a) α =0.01, n=20, from table V we find the following critical values 6.84 and 38.58 b) α =0.05, n=12, from table V we find the following critical values 3.82 and 21.92 c) α =0.10, n=15, from table V we find the following critical values 6.57 and 23.68 9-64 a) α =0.01, n=20, from table V we find = 2 1 , n α χ 36.19 b) α =0.05, n=12, from table V we find = 2 1 , n 19.68 c) α =0.10, n=15, from table V we find = 2 1 , n 21.06 9-65 a) α =0.01, n=20, from table V we find = 2 1 , 1 n 7.63 b) α =0.05, n=12, from table V we find = 2 1 , 1 n 4.57 c) α =0.10, n=15, from table V we find = 2 1 , 1 n 7.79 9-66 a) 2(0.1)< P -value<2(0.5), then 0.2< P -value<1 b) 2(0.1)< P -value<2(0.5), then 0.2< P -value<1 c) 2(0.05)< P -value<2(0.1), then 0.1< P -value<0.2 9-67 a) 0.1<1- P <0.5 then 0.5< P -value<0.9 b) 0.1<1- P <0.5 then 0.5< P -value<0.9 c) 0.99<1- P <0.995 then 0.005< P -value<0.01 9-68 a) 0.1< P -value<0.5 b) 0.1< P -value<0.5 c) 0.99< P -value<0.995 9-69 a) In order to use the χ 2 statistic in hypothesis testing and confidence interval construction, we need to assume that the underlying distribution is normal. 1) The parameter of interest is the true standard deviation of performance time σ . However, the answer can be found by performing a hypothesis test on σ 2 . 2) H 0 : σ 2 = .75 2 3) H 1 : σ 2 >.75 2 4) α = 0.05 5) χ 0 2 = () ns 1 2 2 σ 6) Reject H 0 if 2 1 , 2 0 > n where 30 . 26 2 16 , 05 . 0 = 7) n = 17, s = 0.09 χ 0 2 = 23 . 0 75 . ) 09 . 0 ( 16 ) 1 ( 2 2 2 2 = = σ s n 8) Because 0.23 < 26.30 do not reject H 0 and conclude there is insufficient evidence to indicate the true variance of performance time content exceeds 0.75 2 at α = 0.05. P -value: Because χ 0 2 =0.23 the P -value>0.995 b) The 95% one sided confidence interval given below, includes the value 0.75. Therefore, we are not be able to conclude that the standard deviation is greater than 0.75.
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9-30 σ 07 . 0 3 . 26 ) 09 (. 16 2 2 9-70 a) In order to use the χ 2 statistic in hypothesis testing and confidence interval construction, we need to assume that the underlying distribution is normal.
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This note was uploaded on 10/12/2009 for the course IND E 315 taught by Professor Kailashkapur during the Spring '09 term at University of Washington.

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mont4e_sm_ch09_sec04 - Section 9-4 9-63 a) =0.01, n=20,...

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