mont4e_sm_ch11_sec07 - Section 11-7 2 25.35 ^ S = 0.8617 R...

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11-29 Section 11-7 11-50 () 8617 . 0 71 . 159 35 . 25 330 . 2 ˆ 2 2 1 2 = = = YY XX S S R β The model accounts for 86.17% of the variability in the data. 11-51 a) 787 . 0 2 = R The model accounts for 78.7% of the variability in the data. b) There is no major departure from the normality assumption in the following graph. Residual Percent 10 5 0 -5 -10 -15 99 95 90 80 70 60 50 40 30 20 10 5 1 Normal Probability Plot of the Residuals (response is Rating Pts) c) Assumption of constant variance appears reasonable. Fitted Value Residual 110 100 90 80 70 60 10 5 0 -5 -10 Residuals Versus the Fitted Values (response is Rating Pts) 11-52 Use the Results of exercise 11-5 to answer the following questions. a) SalePrice Taxes Predicted Residuals 25.9 4.9176 29.6681073 -3.76810726 29.5 5.0208 30.0111824 -0.51118237 27.9 4.5429 28.4224654 -0.52246536 25.9 4.5573 28.4703363 -2.57033630 29.9 5.0597 30.1405004 -0.24050041
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11-30 29.9 3.8910 26.2553078 3.64469225 30.9 5.8980 32.9273208 -2.02732082 28.9 5.6039 31.9496232 -3.04962324 35.9 5.8282 32.6952797 3.20472030 31.5 5.3003 30.9403441 0.55965587 31.0 6.2712 34.1679762 -3.16797616 30.9 5.9592 33.1307723 -2.23077234 30.0 5.0500 30.1082540 -0.10825401 36.9 8.2464 40.7342742 -3.83427422 41.9 6.6969 35.5831610 6.31683901 40.5 7.7841 39.1974174 1.30258260 43.9 9.0384 43.3671762 0.53282376 37.5 5.9894 33.2311683 4.26883165 37.9 7.5422 38.3932520 -0.49325200 44.5 8.7951 42.5583567 1.94164328 37.9 6.0831 33.5426619 4.35733807 38.9 8.3607 41.1142499 -2.21424985 36.9 8.1400 40.3805611 -3.48056112 45.8 9.1416 43.7102513 2.08974865 b) Assumption of normality does not seem to be violated since the data appear to fall along a straight line. -4 -2 0 2 4 6 8 Residuals Normal Probability Plot 0.1 1 5 20 50 80 95 99 99.9 cumulative percent c) There are no serious departures from the assumption of constant variance. This is evident by the random pattern of the residuals. 26 29 32 35 38 41 44 Predicted Values -4 -2 0 2 4 6 8 Residuals Plot of Residuals versus Predicted 3.8 4.8 5.8 6.8 7.8 8.8 9.8 Taxes -4 -2 0 2 4 6 8 Plot of Residuals versus Taxes d) % 73 . 76 2 R ; 11-53 Use the results of Exercise 11-5 to answer the following questions a) R 2 99 986% = . ; The proportion of variability explained by the model. b) Yes, normality seems to be satisfied because the data appear to fall along the straight line.
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11-31 -2.6 -0.6 1.4 3.4 5.4 Residuals Normal Probability Plot 0.1 1 5 20 50 80 95 99 99.9 cumulative percent c) There might be lower variance at the middle settings of x. However, this data does not indicate a serious departure from the assumptions.
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mont4e_sm_ch11_sec07 - Section 11-7 2 25.35 ^ S = 0.8617 R...

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