mont4e_sm_ch11_sec08 - 11-38Section 11-811-64 a) :=H:1H=...

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Unformatted text preview: 11-38Section 11-811-64 a) :=H:1H= 0.05 18,025.18,025.64.12208.||101.2657.5tttt>===Reject H. P-value = (<0.0005)(2) = <0.001 b) 5.:=H5.:1H= 0.05 2/025.2/1||96.1265.2)17)(0.5)(arctanh 0.8)((arctanh zzzz>===Reject H. P-value = (0.012)(2) = 0.024. c))+0.8nh tanh(arcta)-0.8nh tanh(arcta1717025.025.zzwherez..025196=. 9177.5534.. Because = 0 and = 0.5 are not in the interval, so reject H. 11-65 a) :=H:1>H= 0.05 18,05.18,05.75.122075.734.181.42tttt>===Reject H. P-value < 0.0005 b) 5.:=H5.:1>H= 0.05 zzzz>===05.2/165.17467.1)17)(0.5)(arctanh0.75)((arctanhReject H. P-value = 0.04 c) )0.75nhtanh(arcta1705.zwhere64.105.=z26.2Because = 0 and = 0.5 are not in the interval, reject the nul hypotheses from parts (a) and (b). 11-66 n = 25 r = 0.83 a):=H:1H= 0.05 11-3923,2/23,025.)83.(12383.12069.2137.722ttttrnr>====Reject H. P-value = 0. b) )+0.83nh tanh(arcta)-0.83nh tanh(arcta2222025.025.zzwhere z..025196=. 9226.6471.. a)8.:=H8.:1H= 0.05 2/025.2/196.14199.)22)(8.arctanh 83.(arctanh zzzz>/===Do not reject H. P-value = (0.3373)(2) = 0.6746. 11-67 n = 50 r = 0.62 a):=H:1H= 0.01 48,005.48,005.)62.(14862.12682.2475.522ttttrnr>====Reject H. P-value 0 b) )+0.62nh tanh(arcta)-0.62nh tanh(arcta4747005.005.zzwhere 575.2005.=z. 8007.3358.. c) Yes. 11-68 a) r = 0.933203 b):=H:1H= 0.05 15,2/15,025....
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This note was uploaded on 10/12/2009 for the course IND E 315 taught by Professor Kailashkapur during the Spring '09 term at University of Washington.

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mont4e_sm_ch11_sec08 - 11-38Section 11-811-64 a) :=H:1H=...

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