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mont4e_sm_ch12_sec06

# mont4e_sm_ch12_sec06 - Residuals V er sus P P GF(response...

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Sections 12-6 12-66. a) 2 33 . 0 205 . 189 15 . 26219 ˆ x x y + = b) H j 0 0 : β = for all j H j 1 0 : β for at least one j α = 0.05 5 , 2 , 05 . 0 5 , 2 , 05 . 0 79 . 5 2045 . 17 f f f f > = = Reject H and conclude that model is significant at α = 0.05 0 c) H 0 11 0 : β = H 1 11 0 : β α = 0.05 571 . 2 | | 571 . 2 45 . 2 0 5 , 025 . 3 8 , 025 . , 0 > / = = = = t t t t t p n α Do not reject H and conclude insufficient evidence to support value of quadratic term in model at α = 0.05 0 d) One residual is an outlier 12-47

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Normality assumption appears acceptable Residuals against fitted values are somewhat unusual, but the impact of the outlier should be considered. -50 -40 -30 -20 -10 0 10 20 30 40 50 -1.5 -1.0 -0.5 0.0 0.5 1.0 1.5 Normal Score Residual Normal Probability Plot of the Residuals (response is y) 500 600 700 800 -50 -40 -30 -20 -10 0 10 20 30 40 50 Fitted Value Residual Residuals Versus the Fitted Values (response is y) 12-67. a) 2 495 . 1 232 . 1 633 . 1 ˆ x x y + = b) f 0 = 1858613, reject H 0 c) t 0 = 601.64, reject H 0 d) Model is acceptable. Observation number 10 has large leverage. 12-48