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Unformatted text preview: Name: MA 1021  2008 A Term Section A02
September 9, 2008 Quiz — Sections 1.11.5, 2.12.4, 3.1 1. All students taking MA 1021 in A Term 2008 will take a common ﬁnal
exam on Wednesday evening, October 15, 2008, and Should have already
cleared their calendar for this time. I‘ FALSE (please circle the correct answer — I point) 2. Students taking MA 1021 in A Term 2008 will have unlimited chances to
pass the Basic Skills component of the ﬁnal TRUE orlease circle the correct answer — I point) 3. It is possible for a tangent line to intersect a function at more than one
point. r FALSE (please circle the correct answer w 2 points) ): f(x+h)f(x) 4. The slope predictor ﬁinction is deﬁned as m(x h TRUE 0(please circle the correct answer — 2 points) 5. It is likely that John Paul’s Calculus name today is Geronimo TRUE orlease circle the correct answer — 2 points ~ BONUS question) cos_(x) =1 6. The basic “trig limit identity” says: lim
x—)0 x TRUE or (please circle the correct answer — 2 points) ANSWER KEV? 7. Express the area of a rectangle with ﬁxed perimeter 60 as a function of _ 7
one of its sides. Be sure to give the domain of yoUr function! (10 points) ' C One Caulo‘ M73 ue We»? if X c; O ..
Of X 2 30) This [3 me? ﬂ'hru64 :
TGC'FZLmjle, IF 30L: 5:113 O< K < Git/[Cl ‘ﬁ/la‘f an 1MP“) OK:  7‘7 You are given a rectangle with area 100, Whose width X is less than or
egual to its length. This rectangle is rotated around its Width, forming a
cylinder as shown in the picture below. Express the volume of the cylinder as a function of X. Be sure to give
" the domain ofyour function! (10 points) ‘ (Note: The volume of a cylinder with radius rand height h is: urzh) Shaded area = 100: \ w _ _ _ ___‘./ New “per ﬁ'uz Glow/weak: Clearly, X '> 0
7mm) X33 2 M {5:100}
“Managua ' K 5 {0) anﬁ 5’0: For the right triangle shown below, you are given: A=1+log381
B = (log2 8)X(1+10g4 64) Calculate (8 points) 10. W
X590 Determine lim x—>0 3sin(4x)
5x 3 SkipPK): ‘tm 5x '5 l?’ 1M. __.——3. H
[0 X390 (4 points) 11. llm
X90 1— 0032 9x Determine 4x2 (6p0ints)
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fo 7— ’ x»; o ‘fxz
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¢ ¢ Lf I l 12. You are given the function f (x) = x2 — 6x — 7 Determine the roots of the function Determine the yintercept of the function arm{ermef (AW X110
:3: 0*0'71 *7 Determine the vertex of this parabola VQF'RX' e (3) "/6) On the next page, Sketch a graph of the function.
Please be sure to Label everything! (Note this problem is worth 12 points total, 7. for everything done on this page and the next) Benutiiul .rketell gee: here f(x) = x2  6x — 7 (see previous page for directions) IIIIIITE‘J IIIIII.
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IIIII IIIII. Roots: (FRO) “"A (713)
Yintercept: C" 7/ O)
Vertex: (3/ '45) Other points of interest? )4 £60 T 41 K ~11 #3, C,
8 ‘1 13. 1 You are given f (x) = —
1 + x Use the deﬁnition of the derivative to ﬁnd f '(x) Recall that this is reaily the same as the slope predictor function; and be sure to use the four step process we discussed. (10 points) £(M—L‘) I €60 P7X") 2 "V"  keo 1" I ..L _ J— 2 W I+X+k I+><
IVEO In (l+x)— (“Hm”) km W” : W90 (waxlvex)
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 Spring '08
 TASHJIAN
 Calculus

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