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Unformatted text preview: (c) Is the probability of finding an electron at the energy level E = E C closer to zero one? (1points) Ans: According to Fig. 315, the probability is closer to “zero”. 3. The FermiDirac function is f(E) =1/(1+exp[(EE F )/kT]). On the energy diagram shown below: (a) Which electron (1) or (3) has the highest occupation probability at equilibrium. (2 points) Ans: Since the energy of electron (1) and (3) is the same, the occupation probabilities are equal at equilibrium. (a) Rank the holes (1’), (3’), and (4’) in descending order of their occupation probability at equilibrium. (3 points) Ans: Probability of finding a hole = 1 – f(E). Since f (1’) < f(3’) < f(4’) => 1f (1’) > 1f(3’) > 1f(4’) => hole(1’), hole (3’), hole(4’) in descending order (1) (3) (4) (1') (3') (4') E F x 1 x 2 x 3 x 4 x 5 X E V E C E c E v E i E F E g E g /2 E...
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This note was uploaded on 10/14/2009 for the course ECE 440 taught by Professor Lie during the Fall '09 term at University of Illinois at Urbana–Champaign.
 Fall '09
 Lie

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