This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: (c) Is the probability of finding an electron at the energy level E = E C closer to zero one? (1points) Ans: According to Fig. 315, the probability is closer to zero. 3. The FermiDirac function is f(E) =1/(1+exp[(EE F )/kT]). On the energy diagram shown below: (a) Which electron (1) or (3) has the highest occupation probability at equilibrium. (2 points) Ans: Since the energy of electron (1) and (3) is the same, the occupation probabilities are equal at equilibrium. (a) Rank the holes (1), (3), and (4) in descending order of their occupation probability at equilibrium. (3 points) Ans: Probability of finding a hole = 1 f(E). Since f (1) < f(3) < f(4) => 1f (1) > 1f(3) > 1f(4) => hole(1), hole (3), hole(4) in descending order (1) (3) (4) (1') (3') (4') E F x 1 x 2 x 3 x 4 x 5 X E V E C E c E v E i E F E g E g /2 E...
View Full
Document
 Fall '09
 Lie

Click to edit the document details