10 AtomicOrbitals&QuantumNumbers

10 AtomicOrbitals&QuantumNumbers - What is the...

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1 1 What is the energy difference between the two states of mercury that are associated with the emission of 404 nm light? Draw an energy level diagram to represent what this question is asking you to find? Calculate the result. h = 6.626 x 10 -34 J s c = 3.00 x 10 8 m/s A) 4.92 x 10 -26 J B) 4.92 x 10 -19 J C) 4.92 x 10 -17 J D) Some other answer not close to these. E atom = E photon E photon = h = hc/ 2 = 404 nm photon emitted Asked to find the energy difference between the two energy levels. Need the relationship between E atom and E photon . Need the relationship between E photon and photon wavelength. E atom = E photon E photon = h = hc/ h = 6.626 x 10 -34 J s c = 3.00 x 10 8 m/s    34 8 19 9 6.63 10 3.00 10 / 4.92 10 404 10 xJ s x m s x J xm Energy Level Diagram
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2 3 Question from Reading MSJ 7.4-7.6 Electrons are considered to be particles because they have mass and momentum. Like photons, however, electrons have wave-like properties. Since electrons have wave-like properties, and waves are spread out over space, the position of an electron can not be determined exactly. The probable location of an electron in an atom is described by wave. The amplitude of the wave at any point gives the probability density of finding the electron at that point. Each wave is identified and characterized by _________ numbers. Respond with a number: 2, 3, 4, or 5 4 Summary of New Relationships  = c E photon = h p = h/ E atom or molecule = E f E i E atom or molecule = E photon E n = -2.178 x 10 -18 J / n 2 (for the H atom) n = 1, 2, 3, … an integer E = Change in energy
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10 AtomicOrbitals&QuantumNumbers - What is the...

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