{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

10 AtomicOrbitals&QuantumNumbers

10 AtomicOrbitals&QuantumNumbers - What is the...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
1 1 What is the energy difference between the two states of mercury that are associated with the emission of 404 nm light? Draw an energy level diagram to represent what this question is asking you to find? Calculate the result. h = 6.626 x 10 -34 J s c = 3.00 x 10 8 m/s A) 4.92 x 10 -26 J B) 4.92 x 10 -19 J C) 4.92 x 10 -17 J D) Some other answer not close to these. E atom = E photon E photon = h = hc/ 2 = 404 nm photon emitted Asked to find the energy difference between the two energy levels. Need the relationship between E atom and E photon . Need the relationship between E photon and photon wavelength. E atom = E photon E photon = h = hc/ h = 6.626 x 10 -34 J s c = 3.00 x 10 8 m/s  34 8 19 9 6.63 10 3.00 10 / 4.92 10 404 10 x Js x m s x J x m Energy Level Diagram
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon