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# Quiz 2 - Answer Key - BILD 3 Fall 2008 Professor C Wills...

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BILD 3 Fall 2008 Name: ___________________________ Professor C. Wills PID # : ___________________________ Section: Mon 9-9:50 AM ------------------------------------------------------------------------------------------------------------------------------------------------------- Page | 1 QUIZ 2 Answer Key 1. In a population of ground squirrels, the number of homozygous dominant individuals for a certain trait is 40, the number of heterozygotes is 30, and the number of homozygous recessive is 30. Find the allele frequencies, p and q, and determine whether or not this population is obeying the Hardy-Weinberg law. (Note : Use a 10% cutoff for deviation of actual values from expected values .) ( 4 pts ) Define alleles/genotypes A = dominant allele, a = recessive allele AA = homozygous dominant (40) Aa = heterozygote (30) Aa = homozygous recessive (30) p = f(A) = [2(40) + 30] / [100 (2)] = 0.55 q = f(a) = 1 f(A) = 1 p = 0.45 or q = f(a) = [2(30) + 30] / [100 (2)] = 0.45 f(AA) = p 2 = (0.55) 2 = 0.3025 or f(aa) = q 2 = (0.45) 2 = 0.2025 or f(Aa) = 2pq = 2(0.55)(0.45) = 0.495 If following H-W, expected AA individuals = f(AA) x total # organisms in population = (0.3025) x (100) = 30.25 individuals or expected aa individuals = f(aa) x total # organisms in population = (0.2025) x (100) = 20.25 individuals or expected Ab individuals = f(Aa) x total # organisms in population = (0.495) x (100) = 49.5 individuals Since the actual AA individuals of 40 is more than 10% deviation away from the expected AA individuals of 30.25, this

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Quiz 2 - Answer Key - BILD 3 Fall 2008 Professor C Wills...

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