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# PS4 - composition of the equilibrium vapor c Now what is...

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ChBE 3110, Fall Semester, 2009 Chemical Engineering Thermodynamics II Problem Set Four 1. Now use the same data from Problem Set Three from Brown & Smith for benzene (1) and ethanol (2) at 45ºC to calculate and plot the activity coefficients for both components. x 2 y 2 P (bars) 0 0 0.2939 0.0374 0.1965 0.3613 0.0972 0.2895 0.3953 0.2183 0.3370 0.4088 0.3141 0.3625 0.4124 0.4150 0.3842 0.4128 0.5199 0.4065 0.4100 0.5284 0.4104 0.4093 0.6155 0.4343 0.4028 0.7087 0.4751 0.3891 0.9591 0.8201 0.2711 1.0000 1.0000 0.2321 2. As best you can, represent the activity coefficients from the previous problem with the following expressions and compare (graphically) to the data. a. A single constant expression: 2 1 2 2 2 1 ln ln x B x B γ = = b. A two-constant expression: ( ) ( ) 2 1 2 2 2 2 1 1 ln 4 3 ln 4 3 x B C x x B C x = = + 3. Water (1) and benzene (2) are added to an empty vessel at 298ºC. a. What is the pressure and composition of the equilibrium vapor? b. Now methane is added at 5 atm partial pressure. What is the pressure and

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Unformatted text preview: composition of the equilibrium vapor? c. Now what is the composition of the two liquid phases. Data (all at 25ºC) : 4 4 , , 4150 .; 505 .; ( ) 0.195 ; ( ) 0.511 ; CH water CH benzene sat sat i i H atm H atm P water atm P benzene atm = = = = 4. A mixture consists of equimolar amounts of hexane (1) – cyclohexane (2) – methyl cyclohexane (3). Assume Raoult’s Law. It is to be flashed at the conditions below; determine in each case the mole fractions in the two phases all x i and y i , and the fraction liquid formed, L. a. T = 30ºC, P = 0.2 atm. b. T = 80ºC, P = 1 atm. 5. A mixture of the composition listed below is to be flashed at 200 psi and 145ºF. Using the DePriester K-factor chart in the text, find the fraction vapor formed V and all the mole fractions in the two phases x i and y i . Compound Mole Fraction Propane 0.50 i-Butane 0.30 n-Butane 0.15 n-Pentane 0.05...
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PS4 - composition of the equilibrium vapor c Now what is...

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