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Unformatted text preview: composition of the equilibrium vapor? c. Now what is the composition of the two liquid phases. Data (all at 25ºC) : 4 4 , , 4150 .; 505 .; ( ) 0.195 ; ( ) 0.511 ; CH water CH benzene sat sat i i H atm H atm P water atm P benzene atm = = = = 4. A mixture consists of equimolar amounts of hexane (1) – cyclohexane (2) – methyl cyclohexane (3). Assume Raoult’s Law. It is to be flashed at the conditions below; determine in each case the mole fractions in the two phases all x i and y i , and the fraction liquid formed, L. a. T = 30ºC, P = 0.2 atm. b. T = 80ºC, P = 1 atm. 5. A mixture of the composition listed below is to be flashed at 200 psi and 145ºF. Using the DePriester K-factor chart in the text, find the fraction vapor formed V and all the mole fractions in the two phases x i and y i . Compound Mole Fraction Propane 0.50 i-Butane 0.30 n-Butane 0.15 n-Pentane 0.05...
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- Spring '08
- Thermodynamics, Chemical Engineering Thermodynamics, Chemical Engineering Thermodynamics II, activity coefficients, equilibrium vapor