Reversible Isothermal Process in a Perfect Gas

Reversible Isothermal Process in a Perfect Gas - Chapter 1...

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Chapter 1 1 atm = 760 torr = 101325 Pa 1 L = I dm 3 = 1000cm 3 K = 273 + ° C The General Ideal-Gas Equation PV = nRT ; R = 82.06 cm 3 ∙atm/mol∙K = 8.3145 J/mol∙K PV = mRTM P = ρ RTM ; ρ = m/V Thermal Expansivity α = 1Vm∂Vm∂TP Isothermal Compressibility κ = -1Vm∂Vm∂PT ∂P∂TVm= α κ Ideal Gas Mixtures PV = n tot RT Partial Pressure (P i ) = x i P P i = niRTV Chapter 2 Reversible P-V work dw rev = -P dV Heat C p = dqpdT = H TP C V = dqvdT = U TV q = TiTfCvdT = n . TiTfCv mdT The First Law of Thermodynamics ∆U = q + w dU = dq + dw constant volume = no work Cyclic Process - ∆U = 0 Joule Coefficient μ J = ∂ ∂ T VU Joule-Thomson Coefficient μ JT =
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This note was uploaded on 10/19/2009 for the course CHEM CHEM 131 taught by Professor Lindenberg during the Spring '09 term at UCSD.

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