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Unformatted text preview: The compression is reversible and adiabatic so constant s. From Eq.8.28 s 2 = s 1 s o T2 = s o T1 + Rln ( P 2 /P 1 ) = 6.83521 + 0.287 ln16 = 7.63094 T 2 = 631.9 K, h 2 = 641 kJ/kg Energy equation with compressor work in w C = 1 w 2 = h 2 h 1 = 641  290.43 = 350.57 kJ/kg Energy Eq. combustor: h 3 = h 2 + q H = 641 + 960 = 1601 kJ/kg State 3: (P, h): T 3 = 1471 K , s o T3 = 8.58811 kJ/kg K The expansion is reversible and adiabatic so constant s. From Eq.8.28 s 4 = s 3 s o T4 = s o T3 + Rln ( P 4 /P 3 ) = 8.58811 + 0.287ln(1/16) = 7.79238 T 4 = 734.8 K, h 4 = 751.11 kJ/kg Energy equation with turbine work out w T = h 3 h 4 = 1601  751.11 = 849.89 kJ/kg Now the net work is w net = w T w C = 849.89 350.57 = 499.32 kJ/kg The total required power requires a mass flow rate as m . = W . net w net = 14 000 499.32 kW kJ/kg = 28.04 kg/s...
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This note was uploaded on 10/20/2009 for the course MECHENG MEecheng 3 taught by Professor Borgnakke during the Fall '09 term at University of Michigan.
 Fall '09
 Borgnakke
 Combustion

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