This

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’
-Pb
’
=0.1 for deltah=1ft
Asin((Pa
’
-Pb
’
)/(deltah*(gamma-gammaB)))
p
atm =gamma*
h+p
vapor

I_xc=PI*R^4/4
y_R=I_xc/(y_c*A)+y_C
distance below the shaft to the center of the pressure is y_R-y_C
∑
M_C=0=F_R*(y_R-Y_C)

Example 2.8 A pressurized tank contains oil (SG = 0.90) and has a square, 0.6-m by 0.6-m plate bolted to its side. When
the pressure gage on the top of the tank reads 50kPa, what is the magnitude and location of the resultant force on the
attached plate? The outside of the tank is at atmospheric pressure.
F_1=(P_s+gamma*h1)*A
F_2=1/2*gamma(h2-h1)/A
F_R=F_1+F_2
M_0=-F_R*y_0+F_1*.3
Example 2.9 The 6-ft-diameter drainage conduit is half full of water at rest. Determine the magnitude and line of action
of the resultant force that the water exerts on a 1-ft length of the curved section BC of the conduit wall.
F1=gamma*hc*A
Weight=gamma*volume
Fh=F1
Fv=Weight
FR=sqrt(Fh^2+Fv^2)
Fbouyant=gamma*Volume
Buoyant force passes through the centroid of the
displaced volume. The point through which the
buoyant force acts is called the center of buoyancy.

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