Unformatted text preview: it. The estimates were 0.7816, 0.8676, 0.8631, and 0.9530, and the same number of subintervals were used in each case. (a) Which rule produced which estimate? Ln = 0.9530 [ 0.9530 ] Tn = 0.8676 [ 0.8676 ] Mn = 0.8631 [ 0.8631 ] Rn = 0.7816 [ 0.7816 ] (b) Between which two approximations does the true value of the integral lie? 0.8631 [ 0.8631 ] (smaller approximation) 0.8676 [ 0.8676 ] (larger approximation) pts 1 0.25/0.25 2 0.25/0.25 3 0.25/0.25 4 0.25/0.25 5 .2/.2 6 .2/.2 7 .2/.2 8 .2/.2 9 .2/.2 10 0.5/0.5 11 0.5/0.5 12 0.5/0.5 13 0.5/0.5 14 0.25/0.25 4.25/4.25 subs 1/20 2/20 1/20 2/20 1/20 3/20 5/20 4/20 2/20 1/20 1/20 1/20 1/20 3/20 2....
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This note was uploaded on 10/21/2009 for the course MATH MA241 taught by Professor Hubbard during the Spring '09 term at N.C. Central.
 Spring '09
 Hubbard
 Calculus

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