# HW3_pdf - arango(da2356 – HW03 – markert –(58710 1...

This preview shows pages 1–3. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: arango (da2356) – HW03 – markert – (58710) 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Will the light from two very close stars pro- duce an interference pattern? 1. No; light from two very close stars is not likely to have the same frequency. correct 2. Yes; strong light from the two stars cre- ates very clear interference patterns. 3. Yes; if they are very close to each other, the light has large overlapping area. 4. No; the light is too strong to produce a discernable interference pattern. Explanation: Light from a pair of stars will not produce an interference pattern because the waves of light from the two separate sources have dif- ferent frequencies and thus are incoherent; when combined they smudge. Interference occurs when light from a single source divides and recombines. 002 10.0 points Diffraction is most noticeable when 1. λ << d. 2. d λ → ∞ . 3. d λ → . correct 4. λ = d. 5. λ d → . Explanation: Solution Diffraction is most noticeable when d λ → 003 10.0 points Light falls on two slits spaced 0.380 mm apart. The angle between the first dark fringe and the central maximum is 0 . 0818 ◦ . What is the wavelength of the light? Correct answer: 1085 . 04 nm. Explanation: Basic Concept: d (sin θ ) = parenleftbigg m + 1 2 parenrightbigg λ, m = 0 , ± 1 , ± 2 , ··· Given: d = 0 . 380 mm θ = 0 . 0818 ◦ m = 0 Solution: λ = d (sin θ ) m + 1 2 = (0 . 38 mm)(sin 0 . 0818 ◦ ) . 5 · 1 m 1000 mm · 10 9 nm 1 m = 1085 . 04 nm 004 (part 1 of 3) 10.0 points In an arrangement to demonstrate double-slit interference, λ = 389 nm, θ = 0 . 886 ◦ , and d = 0 . 167 mm. For light from the two slits interfering at this angle, what is the path difference in mil- limeters? Correct answer: 0 . 00258232 mm. Explanation: Let : θ = 0 . 886 ◦ and d = 0 . 167 mm . Δ x = d sin θ = (0 . 167 mm) sin 0 . 886 ◦ = . 00258232 mm . 005 (part 2 of 3) 10.0 points arango (da2356) – HW03 – markert – (58710) 2 The path difference represents how many wavelengths? Correct answer: 6 . 63836. Explanation: Let : λ = 389 nm Δ x = n λ n = Δ x λ = . 00258232 mm 389 nm 10 6 nm 1 mm = 6 . 63836 . 006 (part 3 of 3) 10.0 points Will the interference correspond to a maxi- mum, a minimum, or an intermediate condi- tion? 1. minimum 2. intermediate correct 3. None of these 4. Unable to determine 5. maximum Explanation: The condition for maxima is Δ x = mλ , m = 0 , ± 1 , ± 2 , ··· and the condition for minima is Δ x = parenleftbigg m + 1 2 parenrightbigg λ , m = 0 , ± 1 , ± 2 , ··· . Δ x = 6 . 63836 λ , so the interference corre- sponds to a intermediate....
View Full Document

{[ snackBarMessage ]}

### Page1 / 7

HW3_pdf - arango(da2356 – HW03 – markert –(58710 1...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online