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Unformatted text preview: Version 014/AAADC – Quiz 2 – Lyon – (53385) 1 This printout should have 3 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 1 2 3 4 5 BACK NEXT AA AB AC AD BA CC CD 001 10.0 points A mixture of NaNO 3 and Na 2 SO 4 of mass 5.37 g contains 1.61 g of sodium. What is the percentage by mass of NaNO 3 in the mixture? 1. 40.2% NaNO 3 2. 30.6% NaNO 3 3. 45.3% NaNO 3 correct 4. 60.7% NaNO 3 5. 35.4% NaNO 3 6. 50.3% NaNO 3 Explanation: m total = 5.37 g m Na = 1.61 g Let x = g of mol NaNO 3 Then 5 . 37 x = g of Na 2 SO 4 Find the weight % of Na in each compound Na NaNO 3 = 23 . 23 . 0 + 14 . 0 + 3(16 . 0) × 100% = 27 . 1% Na Na 2 SO 4 = 2(23 . 0) 2(23 . 0) + 32 . 07 + 4(16 . 0) × 100% = 32 . 4% Therefore (%Na NaNO 3 )(m NaNO 3 ) +(%Na Na 2 SO 4 )(m Na 2 SO 4 ) = 1 . 61 g parenleftbigg 27 . 1 100 parenrightbigg x + parenleftbigg 32 . 4 100 parenrightbigg (5 . 37 x ) = 1 . 61 1 . 739 1 . 61 = 0 . 324 x . 271 x . 053 x = 0...
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This note was uploaded on 10/21/2009 for the course CH 53395 taught by Professor Lyon during the Spring '09 term at University of Texas.
 Spring '09
 Lyon

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