problem32_13

problem32_13 - 32.13: a) I = b) Emax 1 2 0 cEmax ; Emax =...

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Unformatted text preview: 32.13: a) I = b) Emax 1 2 0 cEmax ; Emax = 0.090 V m, so I = 1.1 10 -5 W m 2 2 = cBmax so Bmax = Emax c = 3 .0 10 -10 T 2 -5 2 3 2 c) Pav = I (4r ) = (1.075 10 W m ) (4 ) (2.5 10 m) = 840 W d)Calculation in part (c) assumes that the transmitter emits uniformly in all directions. ...
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This note was uploaded on 10/21/2009 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.

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