problem30_20

problem30_20 - 30 V 30.20(a i max = 1000 = 0.030 A = 30 mA...

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Unformatted text preview: 30 V 30.20: (a) i max = 1000 = 0.030 A = 30 mA, long after closing the switch. b) - i = imax (1 - e -t / ( L / R ) ) = 0.030 A1 - e 10 s = 0.0259 A VR = Ri = (1000 ) (0.0259 A) = 26 V 20 s VL = Battery - VR = 30 V - 26 V = 4.0 V di (or, could use V L = L dt at t = 20 s) c) ...
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This note was uploaded on 10/21/2009 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.

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