problem30_13

problem30_13 - 30.13: U = 1 2 0 N 2 Al 2 LI = 2 4r 4rU 4...

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30.13: πr Al N μ LI U 4 2 1 2 2 0 2 = = turns. 2850 A) 0 . 12 ( ) m 10 00 . 5 ( J) (0.390 m) 150 . 0 ( 4 4 2 2 4 0 2 0 = × = =
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This note was uploaded on 10/21/2009 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.

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