problem32_07

Problem32_07 - 32.7 a = c 3.00 108 m s = = 361 m f 8.30 10 5 Hz 2 2 = = 0.0174 m 1 b k = 361 m c = 2 f = 2(8.30 10 5 Hz = 5.21 10 6 rad s E max =

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32.7: a) m. 361 Hz 10 30 . 8 s m 10 00 . 3 λ 5 8 = × × = = f c b) 1 m 0174 . 0 m 361 2 λ 2 - = = = π π k c) s. rad 10 21 . 5 ) Hz 10 30 . 8 ( 2 2 6 5 × = × = = π f ω π . m V 0145 . 0 ) T 10 82 . 4 ( ) s m 10
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This note was uploaded on 10/21/2009 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.

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