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problem30_18 - 30.18:a B = 0 NI 0(600(2.50 A = = 4.35 mT 2r...

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30.18: a) . mT 35 . 4 ) m 0690 . 0 ( 2 ) A 50 . 2 ( ) 600 ( 2 0 0 = = = π μ π μ r NI B b) From Eq. (30.10), . m / J 53 . 7 2 ) T 10 35 . 4 ( 2 3 0 2 3 0 2 = × = = - μ μ B u c) Volume . m 10 52 . 1 ) m 10 50 . 3 ( ) m 0690 . 0 ( 2 2 V 3 6 2 6 - - × = × = = π π rA d) . J 10 14 . 1 ) m 10 52 . 1 ( ) m / J 53 . 7 ( 5 3 6 3 - - × = × = = uV U e) . H 10 65 . 3 ) m 0690 . 0 ( 2 ) m 10 50 . 3 ( ) 600 ( 2 6 2 6 2 0 2 0 - - × = × = = π μ π μ r A N L J 10
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