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Unformatted text preview: You write that in the box that its pointing to. The final answer is called a transfer function. Box 1,2,3 are on the top row from left to right. Box 4 is on the bottom row Q o (t p )= maximum point Other one equals the assymtope Weird symbol is called zeta Period is the time it takes to reach the max multiplied by two 2.59*2 Krc in question Prc is period You write that in the box that its pointing to. The final answer is called a transfer function. Box 1,2,3 are on the top row from left to right. Box 4 is on the bottom row Q o (t p )= maximum point Other one equals the assymtope Weird symbol is called zeta Period is the time it takes to reach the max multiplied by two 2.59*2 Krc in question Prc is period AK s =500 [lux] the horizontal assymtope C/R=K s /(Ts+1) A=10 [watt] in the question Therefore K s =500/10=50 [lux/watt] Now we calculate T C=AK s (1e1 ) C=500 x .632 C=316 We now look for 316 on the graph, which happens to be at T=4 seconds therefore C/R=50/(4s+1) These are the main equations you need: You write that in the box that its pointing to. The final answer is called a transfer function.You write that in the box that its pointing to....
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This note was uploaded on 10/23/2009 for the course HES 2340 taught by Professor Tomedwards during the Three '09 term at Swinburne.
 Three '09
 tomedwards

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