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Unformatted text preview: = - 0 A Bro2 = ro BA (Equ 5) Substitute B and A into equation 5 = . ro 102 017 449 621 043 = . ( ) ro 0 045342 m = - Thickness ro ri = .- . 0 045342 0 045 = . ( ) 0 000342 m = . ( ) 0 34 mm Tolerance: Due to the thickness of the chamber being very small, it was decided to have changed it to 1mm. Therefore the thickness of the chamber is now 1mm. The tolerance of the chamber is - . + . 1 0 4 0 5 . Other analysis needed to be don e Thermal fatigue o To ensure the chamber can withstand the constant thermal expansion and shirking of the material due to the fluctuation of temperature. Surface fatigue wear o To calculate the life cycle of the chamber to withstand the required life of (insert life cycle) Thermal shock o To ensure the chamber does not experience cracking due to rapid increase of heat. Fretting fatigue wear (is it the same as surface fatigue wear?) o...
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- Three '09