CH 16_student_6_per_page_sp07

# 0 l of naoh to pure water calculate h3o and oh pure

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: late [H3O+] and [OH-]. pure Solution 2 H2O(liq) H3O+(aq) + OH-(aq) O(liq) Le Chatelier predicts equilibrium shifts to Le Chatelier predicts the ____________. [H3O+] < 10-7 at equilibrium. [H Set up a ICE table. Slide 17 of 48 CHM 25 SP07 2 H2O(liq) H3O+(aq) + OH-(aq) O(liq) initial 0 0.0010 change +x +x equilib x 0.0010 + x Kw = (x) (0.0010 + x) Because x << 0.0010 M, assume Because [OH-] = 0.0010 M [OH +] = K / 0.0010 = 1.0 x 10-11 M [H3O w Slide 18 of 48 You add 0.0010 mol of NaOH to 1.0 L of NaOH to pure water. Calculate [H3O+] and [OH-]. pure Solution CHM 25 SP07 CHM 25 SP07 3 You add 0.0010 mol of NaOH to 1.0 L of pure water. NaOH to Calculate [H3O+] and [OH-]. Calculate Solution 2 H2O(liq) H3O+(aq) + OH-(aq) O(liq) [H3O+] = Kw / 0.0010 = 1.0 x 10-11 M This sol...
View Full Document

## This note was uploaded on 10/24/2009 for the course CHEM 025 taught by Professor X during the Spring '06 term at Lehigh University .

Ask a homework question - tutors are online