CH 16_student_6_per_page_sp07

0 l of naoh to pure water calculate h3o and oh pure

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Unformatted text preview: late [H3O+] and [OH-]. pure Solution 2 H2O(liq) H3O+(aq) + OH-(aq) O(liq) Le Chatelier predicts equilibrium shifts to Le Chatelier predicts the ____________. [H3O+] < 10-7 at equilibrium. [H Set up a ICE table. Slide 17 of 48 CHM 25 SP07 2 H2O(liq) H3O+(aq) + OH-(aq) O(liq) initial 0 0.0010 change +x +x equilib x 0.0010 + x Kw = (x) (0.0010 + x) Because x << 0.0010 M, assume Because [OH-] = 0.0010 M [OH +] = K / 0.0010 = 1.0 x 10-11 M [H3O w Slide 18 of 48 You add 0.0010 mol of NaOH to 1.0 L of NaOH to pure water. Calculate [H3O+] and [OH-]. pure Solution CHM 25 SP07 CHM 25 SP07 3 You add 0.0010 mol of NaOH to 1.0 L of pure water. NaOH to Calculate [H3O+] and [OH-]. Calculate Solution 2 H2O(liq) H3O+(aq) + OH-(aq) O(liq) [H3O+] = Kw / 0.0010 = 1.0 x 10-11 M This sol...
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This note was uploaded on 10/24/2009 for the course CHEM 025 taught by Professor X during the Spring '06 term at Lehigh University .

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