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Slide 3 of 48 Slide 4 of 48 CHM 25 SP07 Acid Ionization Constant
acid base conjugate base conjugate acid CH3CO2H + H2O Kc= CH3CO2- + H3O+ [CH3CO2-][H3O+] [CH3CO2H][H2O] [CH3CO2-][H3O+] = 1.8×10-5 [CH3CO2H] Ka= Kc[H2O] = Slide 5 of 48 CHM 25 SP07 Slide 6 of 48 CHM 25 SP07 CHM 25 SP07 1 Base Ionization Constant
base acid conjugate conjugate base acid NH3 + H2O Kc= NH4+ + OH- [NH4+][OH-] [NH3][H2O] [NH4+][OH-] = 1.8×10-5 [NH3] Kb= Kc[H2O] = Slide 7 of 48 CHM 25 SP07 Slide 8 of 48 CHM 25 SP07 A Weak Base A Weak Acid Slide 9 of 48 CHM 25 SP07 Slide 10 of 48 CHM 25 SP07 A Strong Acid In the equilibrium system described by: PO43- (aq) + H2O(1) HPO42 -(aq) +OH-(aq) Brønsted-Lowry theory would designate:
1. PO43- and H2O as the bases 2. H2O and OH- as a conjugate pair 3. HPO42- and OH- as the...
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