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Lecture02 - Displaement Speed 3 Vela-city — Kinematics in...

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Unformatted text preview: Displaement Speed 3: Vela-city — Kinematics in One Dimension Kinematics in fine Dimensiun — Displacmem Speed 3: Vela-city Outline Displacment Kinematics in fine Dimensiun — Displacment Speed 3: "I.I"eli::-i:in.r Outline Displacment Speed 3; Velocity Kinematics in lIflinre Dimensiun — Displacment Speed 3: Velccity Kinematics in One Dimension II- Kinematics deals with the ccncepts that are needed tc describe mcticn. In- Dynamics deals with the effect that forces have an mcticn. Ir Together. kinematics and dynamics farm the branch of physics kncwn as Mechanics. Kinematics in lIE'tne Dimensiun — Displacment Speed 3: Velocity Displacement It in = initial position II- if = final position In ; II- fii’ = i’ — ifl=displacement II- Displacement: a vector that points from an objects initial position to its final position and has a magnitude that is the shortest distance between the two positions. n Dis-Iaeement = oi Kinematics in lCine Dimension — Displecmen‘t Speed 3: Velflcity Displacement Initial peeitien Displacement ia=2.0m Ai=5.0m i = 7_0 In Final position h- an? = i’ — ifl=?.0m - 2.0m =5.Um Kinematics in Cine Dimeneien Dlsp Iacmen‘t Speed 3.: Ill..I"+alI:H:i1:'_nfr Displacement Initial pusitinn in = 7.0m Displacement Ai = —5.0 111 Final pusitiun i=2.0m II- M = i‘ — 553:2.Dn1 - ?.Drn =-5.Um Kinematics in Cine Dimensiun Displacement Speed 3: Veleeity Displacement Initial poeifien i0 = —2.0 III Ag = 7.0 III Displacement 4—.- '— Finel peeitien i = 50 III h- i: fii+in =?.Dn1 - ?.Um =5.Dm Kinematics in lIflllne Dimeneien Dieplacment Speed 3: Velocity Displacement Ir- Listed below are three pairs of initial and final positions that lie along the x axis. Using the concept of displacement decide which pairs give a positive displacement and which a negative displacement. Explain. Initial position 1m Final position x m m Wm m-..“ Kinematics in lIE'ine Dimension Disp lacrnent Speed EL Velmitv Speed 3; Velocity II- Average speed is the distance traveled divided by the time required to cover the distance. Distance Average Speed = m I! SI units for speed: meters per secend (m /s) Kinematics in lIflllne Dimensiun — Disp Iacmen‘t Speed Fe "lil'ielInsanity:r Speed 3; Velocity II- Hew far dees a jogger run in 1.5 hours (5 400 s) if his average speed is 2.22 m/s? Distance = Average Speedx Elapsed Time = 2.22 m/sx5 400 s = 12 000 m. Kinematics in lIflllne Dimensien — Disp lacrnent Speed EL Viability Speed 3; Velocity II- Average velucity is the displacement traveled divided by the time required to cover the distance. D' | t Average Velocity = Isl) acemen Elapsed Time {v}— “—1!” —E _ t—tg _ m Kinematics in lIfllne Dimensiun Disp lacment Speed Er: Vfliflfiity Speed 3; Velocity gu=Dl r=4.?‘fll ---—|—-—+ o It- And};r Green in the car ThrustSSC d) Still Finish set a world record of 341.1 m/s in __ 1W _ fl - +1609 111 Ir To establish such a record. the . {I} drnrer makes two runs through the course. one in each direction, to I'll-.5955 e-UI nullify wind effects. a (I) I From the data. determine the ““5“ 5"” __ average velocity for each run. ah-lsusm {51' Kinematics in Cine Dimension Disp Iacment Speed EL Velflcity Speed 3; Velocity { "Em :~= ’2‘" — 1 509 ’" = +339.5m/s E _ 4.?40 s {I} t lulu fix _1 609 m I' 4.695: In {:Vmfl }— E— m——342.? ”1/3 a Finiii'l 5hr! {31' Kinematics in Cine Dimensiun Disp Iacment Speed Fa: Velflcity Speed 3; Velocity gu=Dl_ r= JET-ID: F'il'lill’l vgm+ W '4: V533: 21'- = {I Vwier 3* = —V(:raen + Vwmd {I Vwmd 21' = —1.5 m/s “.4595; Inn-.0: *5: Fame” 21' = 341.1 m/s Finish Kinematics in Cine Dimensiun Disp lacrnEmt Speed Er: VEIflCity Instantaneous Velocity I The instantaneous velocity indicates how fast an object moves and the direction of motion at each instant of time. I The instantaneous velocity is the slope of the line tangent to the 3-: vs. t curve. Ir This would be the green line. hr The blue lines show that as fit gets smaller. they approach the green line. Kinematics in Cine Dimension ...
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