CS2800-Number-theory_v.9 - 1 Discrete Math CS 2800 Prof....

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Unformatted text preview: 1 Discrete Math CS 2800 Prof. Bart Selman selman@cs.cornell.edu Module Number Theory 2 The Integers and Division Of course, you already know what the integers are, and what division is However: There are some specific notations, terminology, and theorems associated with these concepts which you may not know. These form the basics of number theory . Vital in many important algorithms today (hash functions, cryptography, digital signatures; in general, on-line security). 3 The divides operator New notation: 3 | 12 To specify when an integer evenly divides another integer Read as 3 divides 12 The not-divides operator: 5 | 12 To specify when an integer does not evenly divide another integer Read as 5 does not divide 12 4 Divides, Factor, Multiple Let a , b Z with a . Def.: a | b a divides b : ( 5 c Z : b=ac ) There is an integer c such that c times a equals b. Example: 3 |- 12 True , but 3 | 7 False . Iff a divides b , then we say a is a factor or a divisor of b , and b is a multiple of a . Ex.: b is even : 2| b . Is 0 even? Is 4? 5 Results on the divides operator If a | b and a | c, then a | (b+c) Example: if 5 | 25 and 5 | 30, then 5 | (25+30) If a | b, then a | bc for all integers c Example: if 5 | 25, then 5 | 25*c for all ints c If a | b and b | c, then a | c Example: if 5 | 25 and 25 | 100, then 5 | 100 (common facts but good to repeat for background) 6 Divides Relation Theorem: 2200 a , b , c Z : 1. a |0 2. ( a | b a | c ) a | ( b + c ) 3. a | b a | bc 4. ( a | b b | c ) a | c Proof of (2): a | b means there is an s such that b = as , and a | c means that there is a t such that c = at , so b + c = as + at = a ( s + t ), so a |( b + c ) also. Corollary: If a, b, c are integers , such that a | b and a | c , then a | mb + nc whenever m and n are integers . 7 More Detailed Version of Proof Show 2200 a , b , c Z : ( a | b a | c ) a | ( b + c ) . Let a , b , c be any integers such that a | b and a | c , and show that a | ( b + c ) . By defn. of | , we know 5 s : b=as , and 5 t : c=at . Let s , t , be such integers. Then b + c = as + at = a ( s + t ) , so 5 u : b + c = au , namely u = s + t . Thus a |( b + c ) . Divides Relation Corollary: If a, b, c are integers , such that a | b and a | c , then a | mb + nc whenever m and n are integers . Proof: From previous theorem part 3 (i.e., a|b a|be) it follows that a | mb and a | nc ; again, from previous theorem part 2 (i.e., ( a | b a | c ) a | ( b + c )) it follows that a | mb + nc 9 The Division Algorithm Theorem: Division Algorithm --- Let a be an integer and d a positive integer. Then there are unique integers q and r, with 0 r < d, such that a = dq+r....
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CS2800-Number-theory_v.9 - 1 Discrete Math CS 2800 Prof....

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