Solution Exercise 5 Part 1 - Pu ELIE. FJHENQE...

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Unformatted text preview: Pu ELIE. FJHENQE CBfiflmw|~© DIE-FEW FINHNQ;NIG 1133332: mm - “71132111123373 :1 nbxw YF = 1,250, SB 2 0, EEIOO T = 0 mm C = 50 + 0.6Yd C = 50 + 0.6(Y—0) = 50 + 0.6Y 1 =350 G :100 AD = 500 + 0.6Y 2:» AD(Y0) % Y0 2 Y0 : 1,250 2» 2 WIPEPH 111*:er - 5 'ur: baa-m :nfinb: 1-1pm - 11-11:: pnw 1‘": HELEN C. E"; 1} Eu E. 13:51“ 1mm :mzpn :1 “on n‘vxw GIVEN” YEE 1250, SB : 0, Bug 0 T = 100 31111 E MPH vmv '3 h. Uzi C = 50 + 0.6Yd =-10+0.6Y Pm‘rm'r “‘ "'- I. AD = 440 + 0.6Y 2;» AD(Y0) = Y0 => Y0 = 14-1 00 r; . : ENDING: MHLTMII Th); muLf;p LIFE-R 1 29C. LU: - mp0. , -L if . h “fi—w .5 . . . g; '_"f_,____"_____.___ '5 t " "1-1.1: . “Emfiégfikfih 3" MP”; ' rhm-Twutfi. 1-5 h -L s {.5 3 rmw “1311359er wan 1351 2.5 mm: Warm 3 nufigpn mm}: - 5 ‘un $11111 :n‘m‘m 11pm - 1111a pnr “fl”: tx'fi AGGREGH‘I‘E 0'1 EQUELIQRNM QUENW’” 3* __._H5_____.__._,_._.___ ‘7wa *WW :2 [WWW mflKGrNfiL PRHPENSW'y 'T'fi EKPANB‘ J '—"—--I--u——-—m—.._ .—.—-—-—-—'— dh_—.__,_,__._#‘__q _ ' ‘1"! Exp}; ; :fifiifi'ini:. Paupamsif—If DuffluT Gap THE “EFLW'WfiRH GRIP TEE Aggie-“Eli «Mm—#Hfljififl 3211171 1575 = ‘31‘35573 33571 4' 5‘53”?! THE YNESJAN ‘BDF'JH mum’ipLiEfi wzxwmfipn in THE: Cara MPE = MPC + MP1 2 0.6 + 0.2 = 0.8 2?” mm: THEE ESP-{l ‘1 E: 5 = ‘mann :135 Qu-rpu‘r 'S-QP 500 = “13111.7 1379 DuT [JuT Gm? 723m my 500 ’JI’E‘PDTJ 75:93 2—2—2100 DEFLfiTmMn-R‘f GM“ R 5 r LIE 4 n‘n'rxpn mafia - 5 'm: ‘wmn :nbnb: 11pm * mm pnr ":"1 Ergmmt} pm‘uT QUEH’““#3\ mum :37: - 2 n‘vxw C(Y;rn) NIPC: 0.6 DUTPUT Gm: 500 : “mm 131:: —— mt'I-"T'II'I’Li ER swam noun N I 5 2 533m“ B E FLHTM am G-np Km“) 100 = umbm “me -— MP1: 0.2 nmm‘? noznn m a: G0 nmm‘? nonnn "I MPE= 0.8 2500 3000 n'rmnb nUJDn NI nfinnxpn mufin - 5 ‘un bum :n‘an‘a: 111mm - 11111»: pnr ‘1'“: ..-._n1..I-«:t:n‘:st IN u—Q‘U'r' SHEEN UINIJ ruunwutu IJ‘I urQHT ijufiggwmg Lwfiumh 53mg) rm‘m 1”}: 1mm - n‘v'wmn mum: ‘mu C(Y;rn) ' qufpu‘r‘ Gflfi MPG: 0-6 . 500 = 131m 1319 -— ‘muL‘l‘T'PLIE-Q 11mm“? noun NI 5 = 71933:?! DEFLfi Imam: (3.11;: 100 : ‘JT’E D'f 'WD "'- I(Y;r{:n) MP1: 0.2 PR0 puree. Pu LII-(1'50 AB“: 100 2 50:11:33me raw-rm mwmfi, nmm‘? noun m- MD I 100 * D_1_(-Y;ru) 500=5I100 = KAY AD(Y;rn) 300 : 0.6 I 500 I A C WE: {18 100 = 0.2 -» 500 : 1'31. I 2500000 nmm‘? noun w: 6 nmwpn muwrz - 5 '03: 513.111 :n'n‘v: 11pm: - mm pm” 1"": 5.1+- .'."’a 1 wow 1171 n “’32 wan 11mm mom was mmx 5 C(Y;rn) ' MPG: 0.6 500 = 131m “1325 -- i-mmb nnnnn 5 = Brianna HEW) 100 = ‘Jw‘rm we -- MPI= 0.2 .g 00 = —ATznmmn nwmn . 311nm“) norm G0 60 = AAD : AC 2 100mm '_ imam) 300=5u60 = AY' AD(Y;rn) 240 = 0.6 I 300 + 60 Eric 3 MPE: 0-8 60 = 0.2 II 300 :A1 . 360mm?! noun ntflpn n'rrr'm - 5 'nm ‘rmn :nbjb: 1-1pm: F 111m puny 1"1 TUB?! DTEEE‘? WNW 1113237! 5.3372} FWNW "‘1 .wzvx‘pmn 1339‘? mm mm mom: "1211?: “in man: AT = -100 AG = 100 nmmn . ARE“; 00 ABfiWIhIOO 11mm AC 2 loo-MPG 6 rim-11m 11mm: 5:: Hymn AAD : '1 OOuMPC AAD : 100 AD nmpm 111*er AY:100 'MPC—‘Tranm AY = IOU-5:500 *mx‘m "mm: 511% =100 1.0.6 u5=300 ' *1";er - no“ x51 31mm" 110“ 111*beer wan 240 ' 300 mtg-15:1 33311:: 511% 0 100 nmmn row: 51753.1 : 60 100 HBPUJHZ 5111121 8 ntrxpn mum: - 5 'Dn bum :an5: 11mm F 111%: pm? 1"1 _ mm ‘73: won: wmn mmn :mp 1w mm - 2 ’07: n‘vxw nx‘m nmwnz 5mm mm“? mnb AAD = 100 mum AT "<0 :‘yliflfifi AC 2 AAD = 100 :wwn’? “1‘13 AC : AT- MPC = AT 1-0.6 :mwm: _ mm: M = L02 2 @ =16; MPC 0.6 nuugpn muwn - 5 'na 5mm :nfin‘m 11pm - 1111:: my 1'": bpumn mm mm mm: .mm‘? "um 5:22 am ‘73: amen nunnnn n‘m mom nx ufimm was .n‘m mama mpwnn 13‘? ,n’vw wmx‘m nonnnn but: nfichm: nznmmn now-13:: 113w: ¢ "Tm1 0an “mm: nmm’v .103an nm ‘73: 113mm mom nznwm 712*: 1D nu'rxpn nvr‘m - 5 ‘tm ‘rrm :nfinb: 11pm: - 1111:»: PHI? '1'“: - 1130mm nmpvn mfiwn S + T — G = I :n'mpnm 1130511 nypwn mm 5pm 11W: ATIMPS AT W -AT(1—MPS)<0 11:53:13: mfmn mt infirm bupmw ,nfimen by mean m: awnxnm 1m: .nmmb noun 5:57 mm 5:: puma 5w ummn 1mm ml? 1 1 nuwpn raw-n: - 5 'DD bu‘m :n‘an‘n 11pm - 1111K pnr 1*": - 12 1130mm nmpszn '11:an nuwpn mu‘m - 5 'm: ‘pu‘un :n'yzfvz 1-1pm: — 1111:: rm? 1'": now-13a m: 5172.15 raw: 1w mm - 2 “or: nbxw .mon '11"! '73: 517313 m: 1373‘» n'mmn : rn mph: bfisnnm .500 = 13121:: we «r .100 = wzz‘vmn wan 9 mama mpmn mam: rman 11mm wmwm 1m: mac: or: 51:11:: was «t .ATU- MP0) :2 m: "1335'? mm: mm fits-1323.1 1mm: 511mm; .11: mm“; Tm: am mm: o .vmcbmn .ZSOEAT <2 AT (1 —MPC)= 100 O 13 nu‘rxpn mm: — 5 'rm bum :nbn‘m 11pm - 11-11:: pnw 1"1 _ 14 ADD = C0+10+G0 +MPC-Y - C = C0 +MPC IY— MPC iAT . I =10 G 2 60+ AT ' D = ADO +(1-MPC) AT 1 1—WE 1—MPC [ACzuMPC-AT+MPC-AY=0 nfinfiupn 11113er n 5 '23:: 5mm :nhn‘vzr 11pm: - 1111a pnw '1'“: AY gig-AD- =(14'MPC)LATWM— : AT ...
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This note was uploaded on 10/25/2009 for the course BUSINESS 772 taught by Professor Sadeh during the Spring '07 term at Interdisciplinary Center Herzliya.

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Solution Exercise 5 Part 1 - Pu ELIE. FJHENQE...

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