# PS5solutions - Correction to problem 34: The equation...

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CHEM 3A Problem Set 5 Solutions Chapter 4

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Correction to Problem 26: To calculate K eq , use K eq = e (- Δ G/RT) with R = 0.00198 kcal/molK and T = 298 K. Correct values of K eq and % A & B are shown in the table below. Problem G (kcal/mol) K eq % B % A a 0.94 0.20 17 83 b 0.8 0.26 21 79 c 3.9 0.0014 0.1 99.9 d 1.0 0.19 16 84 e 5.5 9.4E-05 0.01 99.99

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Unformatted text preview: Correction to problem 34: The equation presented is correct, but the final number is wrong. G for this reaction is -0.34 kcal/mol, not -0.81 kcal/mol. G = -1.36 log (64/36) = -0.34 kcal/mol Chapter 5 A. 3 g / 5 mL = 0.6 g/mL 1 cm = 0.1 dm = +2.22 [ ] D = / (l x c) = +2.22 / (0.1 x 0.6) = +37...
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## This note was uploaded on 10/25/2009 for the course CHEM 3A taught by Professor Fretchet during the Spring '08 term at University of California, Berkeley.

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PS5solutions - Correction to problem 34: The equation...

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