{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

PS5solutions

# PS5solutions - Correction to problem 34 The equation...

This preview shows pages 1–8. Sign up to view the full content.

CHEM 3A Problem Set 5 Solutions Chapter 4

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Correction to Problem 26: To calculate K eq , use K eq = e (- Δ G/RT) with R = 0.00198 kcal/molK and T = 298 K. Correct values of K eq and % A & B are shown in the table below. Problem G (kcal/mol) K eq % B % A a 0.94 0.20 17 83 b 0.8 0.26 21 79 c 3.9 0.0014 0.1 99.9 d 1.0 0.19 16 84 e 5.5 9.4E-05 0.01 99.99

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Correction to problem 34: The equation presented is correct, but the final number is wrong. ∆ G ° for this reaction is -0.34 kcal/mol, not -0.81 kcal/mol. ∆ G ° = -1.36 log (64/36) = -0.34 kcal/mol Chapter 5 A. 3 g / 5 mL = 0.6 g/mL 1 cm = 0.1 dm α = +2.22° [ α ] D = α / (l x c) = +2.22° / (0.1 x 0.6) = +37°...
View Full Document

{[ snackBarMessage ]}