ClassProblems_Chapter4

# ClassProblems_Chapter4 - What volume of the NaCl solution...

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Section 4.4 Oxidation # Rules: 1. Elements in their elemental form have an oxidation number of 0. Examples: 2. Monoatomic ions have oxidation numbers equal to their charge. Examples: s 1 : +1: H +1 , Li +1 , Na +1 , K +1 s 2 : +2: Be +2 , Mg +2 , Ca +2 s 2 p 1 : +3: B +3 , Al +3 , Ga +3 s 2 p 2 : +4: C +4 , Si +4 , Ge +4 -1: F - , Cl - , Br - , I - , H - -2: O -2 -3: N -3 3. The sum of the oxidation numbers in a compound = 0. H 2 O K 2 Cr 2 O 7 4. For ions: The sum of the oxidation numbers = the net charge SO 3 2- Cr 2 O 7 2-

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Practice on your own: HCl, AlCl 3 ScCl 3 Mg 3 N 2 [Al(OH) 4 ] -2 S 2 O 3 -2 SO 4 -2 Section 4.4 Oxidation reduction reactions: Complete and balance the following reactions: Zn(s) + HBr(aq) K(s) + H2O(l) Zn(s) + HCl(aq) Cu(s) + FeSO4(aq) Fe(s) + CuSO4(aq) Section 4.5 Calculate the molarity of a solution containing 2.8 g KOH in 250 mL solution.
What is the molarity of hydroxide ion in 0.20 M Ba(OH) 2 aqueous solution? How would you prepare 250 mL of 5.43 M NaCl aqueous solution?

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Unformatted text preview: What volume of the NaCl solution is needed to supply 10.0 g of NaCl? Examples: How many mL of 18.0 M H 2 SO 4 are needed to prepare 200 mL of 1.00 M H 2 SO 4 ? What is the [Na+] in a solution containing 25.0 ml of 1.0 M NaCl and 50.0 mL of 1.0 M Na 2 SO 4 ? What volume of concentrated ammonia is required to produce 500.0 mL of 0.825 M NH 3 ? Concentrated ammonia is 28.0% NH 3 by mass and has a density of 0.898 g/mL. Section 4.6 How many grams of Cl- are present in a sample of water if 20.0 mL of 0.100 M Ag + is needed to react with all the Cl-in the sample? If the sample had a mass of 10.0 g, what was the % Cl-in the sample? How many mL of 0.0800 M NaOH are required to reach the equivalence point using 20.0 mL of 0.120 M HNO 3 ?...
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## This note was uploaded on 10/25/2009 for the course CHEM 121 taught by Professor Wyzlouzil during the Fall '07 term at Ohio State.

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ClassProblems_Chapter4 - What volume of the NaCl solution...

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