This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: exclusive! 14. P(AorB)= P(A) + P(B) <1 if P(A) = .6 P(B) < 1.6 = .4 15. EASY 16. P(A)= .8 P(B)=.65 P(AorB)=.78 P(BA)= P(BandA)/P(A) P(AorB)= P(A) + P(B) P(AandB)= .78= .8 + .65 x = .8375 17. P(AB)= P(A) in order to be independent P(AandB)/(PB)= .3/.6 = .5 = P(A) = YES they are independent 18. 19. .5 so NONE of the above bc half chance for both. 20. 21. E(x) = E * F(x) X= 1, 2, 3 F(x) = 1/6, 2/6, 3/6 E(x) = 1(1/6) + 2(2/6) + 3(3/6) = 2.333 22. 23. P=.5 n*p = 50 n= 100 24. P=.4 n=50 : np(1p)= 50(.4)(.6)=12 25. C (8 on top) (2 on bottom) = .6^2 * .4^6 8!/6!2! = .28 26. C(7 8) = .6^7 * .4^1 + C(8 8) = .6^8 * .4^0 C(8 7)= 8 C(8 8)=1 .4^0=1 8 (.6^7)(.4^1)+(.6^8)...
View
Full
Document
This note was uploaded on 10/26/2009 for the course BIT 2405 taught by Professor Plkitchin during the Spring '08 term at Virginia Tech.
 Spring '08
 PLKitchin

Click to edit the document details