Exam 1 Solutions

Exam 1 Solutions - E15458 Eémofig March 2009 E(l 39 ~3...

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Unformatted text preview: E15458 Eémofig March 2009 E (l. 39:; ~3+orr+LDZR =0 2 Lil: 3—0/7 :- 2’ , =1 2.3mA 8 _,‘_H_, R. )- ~—-79+-- g = o. x; E) 0&2. "7 LU ‘ Ldk : O : -—¢—H” % 3 6w : 2-3+o.7= —O.:5\1 i (“I —+I-+——"t u i- . ~— 5 2, flé:(U—Q(db)—F(Uéfio)—U;C00))€ EC. n ' . - -3 i a /O -3 f f 4. 45 132(10): o +(zo—o)€ “30/0 .01/ . 5—0-7 .QS+IBRB+Q,7 :O. {1913: 1:55 : “(a __ :C :fiI : XOZXABMO =4».%»<103A. = 4.3mA ( Coyfi new owe) Engineer's COmputation Pad ‘ IIIDIHEUI LE“ EEZLE® SQ! mg March 1012.009 2_ KfLovfl-x) I VQE '2 2.5\) = V“; “VG-E =23— =o.sax4l<g_=58:.41l 4. VE‘ _ .55., _ WE " PE 2 _ “ Zn 3;:d; = (fig-fizs 2. 2-475% Lb: “.25.”. Wrap (Hr—fa) ’U/o Z '0 4-(3) RE Ré / fi RE] g: 23:12 12812: 0.9581; . ,J rmm mm: ’4’ . r K ) at 2 £ \2 A 0J0 _ (figs) RE {101 ’V ~ (Di/L F} +6: ifi'fi’3355/ LOIOK 4(30157-9689 W—M— ...
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This note was uploaded on 10/26/2009 for the course EE 438 taught by Professor Cardwell during the Spring '08 term at University of Texas.

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Exam 1 Solutions - E15458 Eémofig March 2009 E(l 39 ~3...

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