Soln3 - Combining the capacitors in parallel, we obtain the...

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EE411 Spring 2008 HW#3 Solution (Q1) 5.92 The top op amp circuit is a non-inverter, while the lower one is an inverter. The output at the top op amp is v 1 = (1 + 60/30)v i = 3v i while the output of the lower op amp is v 2 = -(50/20)v i = -2.5v i Hence, v o = v 1 – v 2 = 3v i + 2.5v i = 5.5v i v o /v i = 5.5 (Q4) 6.22
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Unformatted text preview: Combining the capacitors in parallel, we obtain the equivalent circuit shown below: Combining the capacitors in series gives 1 eq C , where 10 1 30 1 20 1 60 1 C 1 1 eq = + + = 1 eq C = 10 μ F Thus C eq = 10 + 40 = 50 μ F 30 μ F 40 μ F 60 μ F 20 μ F a b...
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This note was uploaded on 10/26/2009 for the course EE 411 taught by Professor Lee during the Spring '07 term at University of Texas at Austin.

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